leetcode

leetcode 412题

Posted by franki on October 11, 2022

leetcode 412 Fizz Buzz

给你一个整数 n ，找出从 1 到 n 各个整数的 Fizz Buzz 表示，并用字符串数组 answer（下标从 1 开始）返回结果，其中：

answer[i] == “FizzBuzz” 如果 i 同时是 3 和 5 的倍数。 answer[i] == “Fizz” 如果 i 是 3 的倍数。 answer[i] == “Buzz” 如果 i 是 5 的倍数。 answer[i] == i （以字符串形式）如果上述条件全不满足。

示例1

输入：n = 3
输出：["1","2","Fizz"]

示例2

输入：n = 5
输出：["1","2","Fizz","4","Buzz"]

示例3

输入：n = 15
输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

思路

按照题意做即可

代码

var fizzBuzz = function(n) {
    const res = [];

    for (let i = 1; i <= n; i++) {
        if (i % 5 === 0 && i % 3 === 0) {
            res[i - 1] = 'FizzBuzz';
        } else if (i % 3 === 0) {
            res[i - 1] = 'Fizz';
        } else if (i % 5 === 0) {
            res[i - 1] = 'Buzz';
        } else {
            res[i - 1] = '' + i;
        }
    }

    return res;
};

复杂度分析:

  • 时间复杂度: O(N)
  • 空间复杂度：O(N)
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